The get_current_platform function could be more specific

mkalioby / django-passkeys

Django Authentication Backend For Passkeys

MIT License

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Closed christian-thieme closed 2 weeks ago

christian-thieme commented 2 weeks ago

Instead of the current approach just return f'{ua.browser.family} / {ua.os.family}'

mkalioby commented 2 weeks ago

The current approach is much easier