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moosetechnology / FAST-Fortran

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Why CallStatement does not use TInvocation ? #187

Open NicolasAnquetil opened 4 months ago

NicolasAnquetil commented 4 months ago

we have: callStatement --|> tWithArguments and in FAST: tInvocation --|> tWithArguments ???

NicolasAnquetil commented 4 months ago

possibly due t the fact that TInvocation implies TExpression Need to correct FAST #66

lsafina commented 3 months ago

try to delete FASTFortranTExpression from FASTFortranTInvocation, see if nothing breaks. if not do ASTFortranCallStatement -> FASTFortranTInvocation