Closed omides248 closed 1 year ago
from pystray import MenuItem as item import pystray from PIL import Image import tkinter as tk window = tk.Tk() window.title("Welcome") def quit_window(icon, item): icon.stop() window.destroy() def show_window(icon, item): icon.stop() window.after(0, window.deiconify) def withdraw_window(): window.withdraw() image = Image.open("lib//assets//icon.ico") menu = (item('Quit', quit_window), item('Show', show_window)) icon = pystray.Icon("name", image, "title", menu) icon.run() window.protocol('WM_DELETE_WINDOW', withdraw_window) window.mainloop()
How to open the app automatically by clicking (left click mouse) on the system icon tray?
Now I have to display app it by right clicking and clicking the show option. I want it to appear with the left click on the quick-up icon. Thankful
show
Thank you for you report.
Depending on the platform on which your application run, this is possible by setting the default argument to True for your default menu item. Please consult the documentation.
default
True
How to open the app automatically by clicking (left click mouse) on the system icon tray?
Now I have to display app it by right clicking and clicking the
show
option. I want it to appear with the left click on the quick-up icon. Thankful