there is a unique solution $x(f) \in L^\infty(\mathbb{R}^+; \mathbb{R}^n)$ of the half-line equation with $||x(f)||_{L^\infty(\mathbb{R}^+)} \leq \delta$.
In our cases, we have that $f(t) = e_2(t) + \frac{\mu}{\nu} \left(1-e^{\nu e^{-t}}\right).$ From Equation 29 of the paper, we deduce that
Today, we looked more carefully at Theorem 11.3.1 of the book. Specifically, the implication clause states that
Then there exist positive constant $\epsilon$ and $\delta$ such that, for every
$$f \in U = \{f \in L^\infty(\mathbb{R}^+; \mathbb{R}^n) \ | \ ||f||_{L^\infty(\mathbb{R}^+)} \leq \epsilon\},$$
there is a unique solution $x(f) \in L^\infty(\mathbb{R}^+; \mathbb{R}^n)$ of the half-line equation with $||x(f)||_{L^\infty(\mathbb{R}^+)} \leq \delta$.
In our cases, we have that $f(t) = e_2(t) + \frac{\mu}{\nu} \left(1-e^{\nu e^{-t}}\right).$ From Equation 29 of the paper, we deduce that
$$||f||_{L^\infty(\mathbb{R})} \leq \mu + e^{\mu-1} + \frac{\mu}{\nu}(e^{\nu}-1).$$
From the proof of Theorem 3.2 on page 319, we want to choose $\delta$ so that
$$||b\delta||{L^1(\mathbb{R})} \leq \frac{c}{1+||r||_{L^1(\mathbb{R})}}, \quad |c|<1.$$
We overestimate
\begin{align}||r||{L^1(\mathbb{R})} = \left|\left| \sum{j=1}^m(-1)^{j-1}k^{\ast j}\right|\right|_{L^1(\mathbb{R})}\end{align}