Closed zmichels closed 8 years ago
Hi Zach,
given a misorientation it is impossible to retrieve the misorientation axis in specimen coordinates. To compute this axis we need a pair of orientations. A list of such pairs of orientations can be computed by the command
[ori1,ori2] = calcMisorientation(ebsd('Olivine'))
Not the misorientation axis in specimen coordinates is computed by
a = axis(ori1,ori2)
You can plot the axes now by
plot(a,'contourf')
In the next version of MTEX 4.2 you can do this directly with plotAxisDistribution.
Ralf.
Ralf,
Thank you much!
best, Zach
Hello Ralf and others,
This is probably an ignorant question, and hopefully has a simple answer. I am uncertain about how to plot the axes of misorientations relative to the principal directions of the specimen/acquisition reference frame.... rather than the crystal reference frame. I am probably missing something quite basic.
Here is an example:
The following plotting commands all seem to visualize the misorientation data relative to the crystallographic directions:
How can I plot the axes of the misorientations relative to the specimen reference frame (i.e., a lower hemisphere plot of the misorientation axes that is orientated relative to the xvector, yvector, zvector specimen directions)?
Any help is greatly appreciated.
Thank you, Zach
For context... here are some other plots
plotPDF of mori data:
ODF for the sample (a mantle xenolith; sample surface cut randomly relative to any mesoscopic fabric):![screen shot 2015-10-28 at 8 26 14 am](https://cloud.githubusercontent.com/assets/8769619/10789845/d3f44842-7d4d-11e5-8c70-467445b88fbf.png)