Closed rubiojr closed 5 years ago
mod.Logln(msg) will write the Pushover tokens to stdout, which isn't ideal if the logs are saved somewhere (when running from systemd for example).
mod.Logln(msg)
Send the debug output to the debug log instead.
mod.Logln(msg)will write the Pushover tokens to stdout, which isn't ideal if the logs are saved somewhere (when running from systemd for example).Send the debug output to the debug log instead.