Unable to store mysql query result inside a variable

[mikias21]

I am trying to query user by email and save the result inside a variable. I tried using await and async, callback and promise but none of them actually work.

const checkEmailUsed = (email) => {
  let sql = "SELECT * FROM users_signup WHERE user_email = ? LIMIT 1";
  return new Promise((resolve, reject) => {
    conn.query(sql, email, (err, res) => {
      if (err) {
        reject(err);
        return;
      }
      resolve(res[0]);
    });
    conn.end();
  });
};

var user = [];
checkEmailUsed("mikias@email.com")
  .then((res) => user.push(res))
  .catch((err) => console.log(err));

console.log(user); // Still []

[mbaumgartl]

The console.log is executed before the promise is fulfilled. This should work:

const checkEmailUsed = (email) => {
  let sql = "SELECT * FROM users_signup WHERE user_email = ? LIMIT 1";
  return new Promise((resolve, reject) => {
    conn.query(sql, email, (err, res) => {
      if (err) {
        reject(err);
        return;
      }
      resolve(res[0]);
    });
    conn.end();
  });
};

var user = [];
checkEmailUsed("mikias@email.com")
  .then((res) => user.push(res))
  .then(() => console.log(user))
  .catch((err) => console.log(err));

[mikias21]

Thank you very much sir. Thank you

On Thu, Jan 21, 2021 at 2:11 AM Marco Baumgartl notifications@github.com wrote:

The console.log is executed before the promise is fulfilled. This should work:

const checkEmailUsed = (email) => { let sql = "SELECT * FROM users_signup WHERE user_email = ? LIMIT 1"; return new Promise((resolve, reject) => { conn.query(sql, email, (err, res) => { if (err) { reject(err); return; } resolve(res[0]); }); conn.end(); });}; var user = [];checkEmailUsed("mikias@email.com") .then((res) => user.push(res)) .then(() => console.log(user)) .catch((err) => console.log(err));

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[Zikoel]

@mikias21 can you mark this issue as closed?