Closed n0rbed closed 1 month ago
If you pass the equation
(x+1)^20
As an array to the solve function like so:
solve([(x+1)^20], x)
It will expand it in the overloaded function, which bypasses the conditions for the special case we have in the main solve function, returning nothing.
P.S. solve((x+1)^20, x) works fine.
solve((x+1)^20, x)
If you pass the equation
As an array to the solve function like so:
It will expand it in the overloaded function, which bypasses the conditions for the special case we have in the main solve function, returning nothing.
P.S.
solve((x+1)^20, x)works fine.