Open GoogleCodeExporter opened 8 years ago
conn.type == 1 stands for TCP.
The test makes sure that all the local addresses returned by psutil can be used
to create a listening socket.
s.bind((conn.local_address[0], 0))
0, here, means, "bind on any port".
I don't know why the test fails. Is 192.168.101.129 associated with a valid
network interface?
What happens if you manually do:
>>> import socket
>>> socket.socket().bind(("192.168.101.129", 0))
...?
Original comment by g.rodola
on 28 Jun 2011 at 7:48
Is this still failing?
Original comment by g.rodola
on 22 Oct 2011 at 11:41
[deleted comment]
Updated csets after the SVN -> Mercurial migration:
r1054 == revision 2985d46279e0
Original comment by g.rodola
on 2 Mar 2013 at 12:01
Original issue reported on code.google.com by
jlo...@gmail.com
on 28 Jun 2011 at 3:46