To create the environment via conda command don't work
To Reproduce
Steps to reproduce the behavior:
conda env create -f environment.yml
conda env create -f environment.yml
Collecting package metadata (repodata.json): - WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.8.0., but conda is ignoring the . and treating it as 1.8.0
WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.7.1., but conda is ignoring the . and treating it as 1.7.1
WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.6.0., but conda is ignoring the . and treating it as 1.6.0
WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.9.0., but conda is ignoring the . and treating it as 1.9.0
done
Solving environment: failed
Information
The problem arises in chapter:
Describe the bug
To create the environment via conda command don't work
To Reproduce
Steps to reproduce the behavior:
conda env create -f environment.yml Collecting package metadata (repodata.json): - WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.8.0., but conda is ignoring the . and treating it as 1.8.0 WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.7.1., but conda is ignoring the . and treating it as 1.7.1 WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.6.0., but conda is ignoring the . and treating it as 1.6.0 WARNING conda.models.version:get_matcher(546): Using . with relational operator is superfluous and deprecated and will be removed in a future version of conda. Your spec was 1.9.0., but conda is ignoring the . and treating it as 1.9.0 done Solving environment: failed
ResolvePackageNotFound:
Expected behavior