code for converting grid to 64 bit variable

[Redpheonix024]

Sir, Can you please link the code for converting the grid into 64 bit varible

[kripanshsharma]

def convert_grid_to_64bit(grid): num_rows = len(grid) num_cols = len(grid[0]) result = 0

for row in range(num_rows):
    for col in range(num_cols):
        if grid[row][col]:
            bit_position = row * num_cols + col
            result |= 1 << bit_position

return result

[nneonneo]

@jishnu2000 The code is here: https://github.com/nneonneo/2048-ai/blob/f5797579369147248bec78cd6ae5f97ce6771c08/2048.py#L30

def to_c_board(m):
    board = 0
    i = 0
    for row in m:
        for c in row:
            board |= int(c) << (4*i)
            i += 1
    return board

There are 16 grid cells, each of which occupy 4 bits in the 64-bit number.

[Redpheonix024]

thanks and how can we improve the ai highscorce i tested it every time it will get struck at 16000 tile with 4096 tile and the game will be over any way of improving the outcome and reach 32000 tiles consistently

[nneonneo]

That’s a bit of an open research problem :)

If you have any such ideas, feel free to submit an issue or pull request!