Angular Build Fails

[tylernchls]

Build completes then get this error

cmd: oc new-app nodeshift/centos7-s2i-web-app:latest~https://github.com/lholmquist/angular-web-app

npm info ok ---> Cleaning up npm cache ----> moving built web application to /opt/app-root/output mv: cannot stat './build/*': No such file or directory error: build error: non-zero (13) exit code from nodeshift/centos7-s2i-web-app@sha256:989207b23a6924d850d8970646c52379df3ec3c278a5

[lholmquist]

When an Angular app is built, the resulting html/js/css is located in the dist/project_name directory. By default this image will look for a directory named build, but you can change this

you need to set the OUTPUT_DIR environment variable to be dist/angular-web-app

[lholmquist]

resolved here https://github.com/lholmquist/angular-web-app/issues/2

[am7ey]

how we do this when using console? Where to set this variable.

[lholmquist]

which console? If it is the web console, that value needs to be set in the buildConfig,

if you are talking about a terminal console, then you can use the oc command with a template like this: https://github.com/lholmquist/angular-web-app#running-on-openshift

or is you are using straight up s2i on the command line, then something like this: s2i build -e OUTPUT_DIR=angular-web-app/dist . nodeshift/ubi8-s2i-web-app:latest angular-web-app

[am7ey]

which console? If it is the web console, that value needs to be set in the buildConfig,

if you are talking about a terminal console, then you can use the oc command with a template like this: https://github.com/lholmquist/angular-web-app#running-on-openshift

or is you are using straight up s2i on the command line, then something like this: s2i build -e OUTPUT_DIR=angular-web-app/dist . nodeshift/ubi8-s2i-web-app:latest angular-web-app

I was able to do this by declare/set the variable using environment tab. Yes I was using web console.

Thanks for your reply.