Open dlfivefifty opened 1 year ago
There is also a variant that could be used for E.
julia> α = 4.453667231591123
4.453667231591123
julia> E = Elliptic.E(1-1/α^2)
1.0608774783105355
julia> E2f1 = convert(eltype(α),π)/2*HypergeometricFunctions._₂F₁(-one(α)/2,one(α)/2,1,1-1/α^2)
1.0608774783105355
julia> @test E ≈ E2f1
Test Passed
From @TSGut (CC @MikaelSlevinsky):