Open M4xi1m3 opened 4 years ago
Hum, supposed to be done as is by a calculator? Or you just wish you could :) ?
A workaround would be P(X<0) + P(0<X<a) + P(X>a) = 1
giving P(X>a) = 1 - 0.5 - 2/11 = 7/22
(supposing X ~ N(0, 1)
) which gives you a.
Which i believe would be the way to achieve this with any other calculator that only offers NormalBcd. Returning the result as is without any details would probably be rejected? Unless Multiple Choice without justification...
But maybe could be added
Expected behavior
I would expect to be able to set both the value.
So would i expect. I'd like to see this feature in the future:)
Describe the bug
Take for example the normal distribution. In an exercise I had P(0 < X < a) = 2/11 and had to solve for a. I wasn't able to specify both the 0 and the 2/11.
To Reproduce
Steps to reproduce the behavior:
Expected behavior
I would expect to be able to set both the value. Here, setting the 2/11 after the 0 removes the 0 and centers the area under the curve.
Environment