Open Guo-Yujia opened 3 years ago
Hi, you may refer to #309
BiFunction<Character, String, Integer> s = new BiFunction<Character, String, Integer>() { public Integer apply(Character c, String s) { return (c + s).length(); } }
I got about the same here BiFunction<Character, String, Integer> s = new BiFunction<Character, String, Integer>() { @Override public Integer apply(Character c, String s) { return (c + s).length(); } };
same BiFunction<Character, String, Integer> s = new BiFunction<Character, String, Integer>() { public Integer apply(Character i, String j) { return (i + j).length(); } }
Summary
Anyone knows what the answer is for this question?
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