Closed talex5 closed 1 year ago
If one fiber tries to force a lazy value while another is already doing it, this will wait for the first one to finish rather than raising an exception (as Stdlib.Lazy does).
Stdlib.Lazy
If one fiber tries to force a lazy value while another is already doing it, this will wait for the first one to finish rather than raising an exception (as
Stdlib.Lazydoes).