Closed msakai closed 1 year ago
Using implicit definition
x ** y = exp (log x * y)
makes its gradient to be
[(y * exp (log x * y)) / x, log x * exp (log x * y)]
and it's problematic when x = 0.
x = 0
Thank you!
@msakai available from v 0.5 : https://hackage.haskell.org/package/ad-delcont-0.5.0.0
Using implicit definition
makes its gradient to be
and it's problematic when
x = 0
.