Open reinaldomoreira opened 6 years ago
propertChanges()
returns an Observable
. What if you do RxObservableField.propertyChanges(observableField).toFlowable()
?
Sorry, I forgot to mention that I already do .toFlowable(), and with this, I end up with a Flowable<? extends String> instead of Flowable
So what's the problem? Your Flowable
must have a type argument.
I don't know why it didn't show in my comment but I said Flowable < String > (not Flowable)
I'm sorry; could you show me some code so I can have a better understanding of the problem? Or maybe a falling/not compiling test?
On Sun, May 20, 2018, 16:57 Reinaldo Moreira notifications@github.com wrote:
I don't know why it didn't show in my comment but I said Flowable < String
(not Flowable)
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Hey all, I don't get it why use ? instead of T directly in RxObservableField<>.propertyChanges(? extends T). If I use like this, I end up with something like Flowable<? extends String> in my code because the compiler won't accept Flowable.