The current pattern was allowing strings like 1\s1234 which is obviously not a valid number. \\. actually matches a \ character following by any char (.).
By getting rid of the extra \ it now matches a . character as expected so we can have proper float values 🙂.
olegbl
commented
1 year ago
The current pattern was allowing strings like
1\s1234which is obviously not a valid number.\\.actually matches a\character following by any char (.).By getting rid of the extra
\it now matches a.character as expected so we can have proper float values 🙂.Example: https://regex101.com/r/pZSUOK/1