20190327 - JS时间相关

[onvno]

JavaScript获取系统当前日期和时间、星期几 方法一：

<script language="javascript"> 
var mydate=new Date(); 
var myyear=mydate.getYear(); 
var mymonth=mydate.getMonth()+1;//注：月数从0~11为一月到十二月 
var mydat=mydate.getDate(); 
var myhours=mydate.getHours(); 
var myminutes=mydate.getMinutes(); 
var myseconds=mydate.getSeconds() 
var myday=mydate.getDay()//注:0-6对应为星期日到星期六 
var xingqi 
switch(myday) 
{ 
case 0:xingqi="星期日";break; 
case 1:xingqi="星期一";break; 
case 2:xingqi="星期二";break; 
case 3:xingqi="星期三";break; 
case 4:xingqi="星期四";break; 
case 5:xingqi="星期五";break; 
case 6:xingqi="星期六";break; 
default:xingqi="系统错误！" 
} 
document.write("现在的时间是：") 
document.write("<br>") 
document.write(""+myyear+"年"+mymonth+"月"+mydat+"日"); 
document.write("<br>") 
document.write(""+myhours+"时"+myminutes+"分"+myseconds+"秒"); 
document.write("<br>") 
document.write(xingqi) 
</script> 

---

方法二： （自定义函数法，然后调用）

<script language="javascript"> 
function xingqi() 
{ 
var a=new Date() 
var myxingqi=a.getDay() 
var b 
switch(myxingqi) 
{ 
case 0:b="星期日";break; 
case 1:b="星期一";break; 
case 2:b="星期二";break; 
case 3:b="星期三";break; 
case 4:b="星期四";break; 
case 5:b="星期五";break; 
case 6:b="星期六";break; 
default:b="系统错误，无法读取日期！"; 
} 
document.write(b) 
} 
xingqi() 
</script> 

---

方法三：（数组方法）

<script language="javascript"> 
var a=new Date() 
var myxingqi=a.getDay() 
var b=new Array() 
b[0]="星期日"; 
b[1]="星期一"; 
b[2]="星期二"; 
b[3]="星期三"; 
b[4]="星期四"; 
b[5]="星期五"; 
b[6]="星期六"; 
document.write(b) 
</script> 
或者 
<script language="javascript"> 
var a=new Date() 
var myxingqi=a.getDay() 
var b=new Array("星期日","星期一","星期二","星期三","星期四","星期五","星期六") 
document.write(b) 
</script>