Closed RDaneelOlivav closed 1 year ago
TypeError: Server.emit() got an unexpected keyword argument 'broadcast'
When launching the any example that launches the rmf comons, gives this error:
This makes the web interface not work.
I tracked the error until here:
simple_api_server.py
Is there a version that I'm not aware of?
execute:
ros2 launch rmf_demos_gz_classic hotel.launch.xml | grep "Server.emit"
You should see that error.
I would imagine that following this tutorial of installation, there shouldn't be any errors: https://github.com/open-rmf/rmf/discussions/267
I will try to do the same but installing rmf from source but I really don't understand why this could be happening. Hve I done something wrong in the installation?
UPDATE: Did the source installation with the exact same results
I moved the issueto rmf_demos
Bug report
TypeError: Server.emit() got an unexpected keyword argument 'broadcast'
Required information:
Description of the bug
When launching the any example that launches the rmf comons, gives this error:
TypeError: Server.emit() got an unexpected keyword argument 'broadcast'
This makes the web interface not work.
I tracked the error until here:
simple_api_server.py
Is there a version that I'm not aware of?
How to reproduce
execute:
ros2 launch rmf_demos_gz_classic hotel.launch.xml | grep "Server.emit"
You should see that error.
Expected behavior
I would imagine that following this tutorial of installation, there shouldn't be any errors: https://github.com/open-rmf/rmf/discussions/267
Screenshots
Additional information
I will try to do the same but installing rmf from source but I really don't understand why this could be happening. Hve I done something wrong in the installation?
UPDATE: Did the source installation with the exact same results