Closed Yung-sheng closed 1 week ago
After apply this commit: https://github.com/openbmc/entity-manager/commit/7fc486f5072a492029ac09374f6238bdadce6690
My platform will create duplicated object.
.----------. .--------. .--------. | mux- |-----| dev D1 | | root |--+--| locked | '--------' '--------' | | mux M1 |--. .----------. | '----------' '--| MY FRU | | .--------. '----------' '--| dev D3 | '--------'
The root bus is 5, and MY FRU bus number is 50. Can see that same object created under FruDevice
root@test:~# busctl --no-pager tree xyz.openbmc_project.FruDevice `-/xyz `-/xyz/openbmc_project `-/xyz/openbmc_project/FruDevice |-/xyz/openbmc_project/FruDevice/MY_FRU `-/xyz/openbmc_project/FruDevice/MY_FRU_0
Is this right to create duplicate object?
After apply this commit: https://github.com/openbmc/entity-manager/commit/7fc486f5072a492029ac09374f6238bdadce6690
My platform will create duplicated object.
The root bus is 5, and MY FRU bus number is 50. Can see that same object created under FruDevice
Is this right to create duplicate object?