Closed ezio416 closed 4 months ago
This new function appears to be ignoring $i passed into it. Passing explicitly \\$i into ImGui functions does work and displays italics correctly, so it does seem to be an issue with this function, not ImGui or the new implementation.
$i
\\$i
This new function appears to be ignoring
$ipassed into it. Passing explicitly\\$iinto ImGui functions does work and displays italics correctly, so it does seem to be an issue with this function, not ImGui or the new implementation.