Closed krypt-n closed 10 years ago
if x is a lambda and y is a builtin, the lval_eq(x->formals,y->formals) would fail. This fixes it by not doing a lambda comparison if a builtin is involved.
Thanks!
if x is a lambda and y is a builtin, the lval_eq(x->formals,y->formals) would fail. This fixes it by not doing a lambda comparison if a builtin is involved.