Closed lgoettgens closed 1 week ago
The map $(g,h) \times m \mapsto g \cdot m \cdot h^{-1}$ does not define a group operation, $(g,h) \times m \mapsto g^{-1} \cdot m \cdot h$ would work:
julia> for _ in 1:10
G_times_H = direct_product(G, H)
(proj_G, proj_H) = canonical_projections(G_times_H)
rep = M([1 0 0;0 0 0])
ord = order(stabilizer(G_times_H, rep, (m,gh) -> inv(proj_G(gh))*m*proj_H(gh))[1])
println(ord)
end
5184
5184
5184
5184
5184
5184
5184
5184
5184
5184
ahh, I think we got confused with right vs left operations. Thanks for your answer.
Consider the action of $GL_2(3) \times GL_3(3)$ on $\mathbb{F}_3^{2 \times 3}$ via $(g,h) \times m \mapsto g \cdot m \cdot h^{-1}$. Repeatedly asking for the order of the stabilizer of some rank 1 matrix results in different results (most of which are wrong).
results in
The correct result is 5184.
If one moves the definition of
G_times_H
in front of the loop, the result stays consistent (but in most cases still wrong).Expected behavior Everytime the same, correct result 5184.
System (please complete the following information): Please paste the output of
Oscar.versioninfo(full=true)
below. If this does not work, please paste the output of Julia'sversioninfo()
and your Oscar version.Thanks to @flyingapfopenguin for finding this.
ping @ThomasBreuer @fingolfin