Open pabryan opened 6 years ago
We can't do anything away from L^2, our methods are very much L^2. This is the price we have to pay in order to be able to build this stuff at such generality. In fact, how do we even define any of these objects away from L^2? we could look at it distributionally, but I can't see how a distributional Laplacian would have a heat kernel?
I'm not sure of what a round cone is? Do you mean a cone that has S^n cross sections? A manifold with such a cone attached is indeed a smooth manifold with a rough metric. This is in my paper with Mike and Sajjad.
I would very much doubt anything rectifiable can be realised as a manifold with rough metric in general. We know that in dimensions > 3, not every Lipschitz manifold can be smoothed. This indicates that it would be impossible in general to pass topological singularities to those in a metric, because one would first need to smooth out the structure of the Lipschitz manifold, which is not always possible.
A general warped product dr^2 + g_N with cross section N will not be a rough metric, because the singularity at r = 0 might be topological. If N = S^n, we're all good.
Not sure about orbifolds at all, but this seems interesting.
Not sure about this stuff at all. I don't think anyone has proved any kind of limit or compactness theorems in the rough metric setting.
We can't talk about RCD for rough metrics because the whole issue is that we don't have a metric structure. BUt you make a point here. Maybe if there was a distance associated to the heat kernel of a rough metric, i.e., the limit lim_{t->0} t log( \rho_t(x,y)) exists and gives rise to a metric, then one can ask what conditions on the rough metric would make (M, d, \mu) an RCD-space. I think we're far from this, but.
It be very helpful to describe some examples, particularly in connection with the heat kernel estimates.