Launch with file that doesn't have .frag extension

[danielchasehooper]

we have some existing shaders in our repo that don't have the .frag extension that we would like to view in glslviewer, is there a way to launch it from the command line without cping to a tmp file with the .frag extension? When you do this you don't get hot reloading for the original file

[patriciogonzalezvivo]

hi @danielchasehooper! For context we use .frag or .fs to distinguish fragment shaders from vertex shader (.vert or .vs). Files with .glsl extensions are a bit ambiguous, that's why usually you see them when they are part of libraries like on https://lygia.xyz.

Solution, you could create file pairs that include the .glsl counter part. For example:

shader.glsl

uniform vec2 u_resolution;
uniform float u_time;
void main() {
   vec4 color = vec4(0.0,0.0,0.0,1.0);
   vec2 uv = gl_FragCoord.xy/u_resolution;
   ...
   gl_FragColor = color;
}

shader.frag

#include "shader.glsl"

This way:

1. you don't have duplicate files
2. glslViewer can track the changes of the original .glsl file
3. the .frag pairs can be easily generated programatically

[danielchasehooper]

we don't use the glsl extension, #include doesn't seem to work if the file doesn't have a glsl extension

It'd be useful if glslviewer had something like a --frag param so that you can launch it like so: glslviewer --frag shaderFileName and it works with any extension.