Following a non existing user will crash onegram

[JulienMaille]

https://www.instagram.com/audrey/

INFO:onegram.session:(xxxxxx) queries.user_info: GET "https://www.instagram.com/audrey/"
Traceback (most recent call last):
  File "C:\Program Files (x86)\Python36-32\lib\site-packages\sessionlib-0.2.1-py3.6.egg\sessionlib\sessionlib.py", line 157, in wrapped
    response = func(*args, **kwargs)
  File "D:\Codez\onegram\onegram\actions.py", line 8, in follow
    return _user_action(session, user)
  File "D:\Codez\onegram\onegram\actions.py", line 52, in _user_action
    user_id = _user_id(session, user)
  File "D:\Codez\onegram\onegram\queries.py", line 84, in _user_id
    return user_info(session, user)['id']
  File "C:\Program Files (x86)\Python36-32\lib\site-packages\sessionlib-0.2.1-py3.6.egg\sessionlib\sessionlib.py", line 157, in wrapped
    response = func(*args, **kwargs)
  File "D:\Codez\onegram\onegram\queries.py", line 14, in user_info
    return _info(session, username=username or session.username)
  File "D:\Codez\onegram\onegram\queries.py", line 101, in _info
    return jsearch(JSPATHS[query], response)
  File "D:\Codez\onegram\onegram\utils\__init__.py", line 22, in jsearch
    raise TypeError()
TypeError

[pauloromeira]

Thanks for reporting the issue. What would you think that could be the default approach: to simply ignore or to raise a specific exception?

[Oyetomi]

Print "user does not exist"..

On Sat, 19 May 2018, 3:01 am Paulo Romeira, notifications@github.com wrote:

Thanks for reporting the issue. What would you think that could be the default approach: to simply ignore or to raise a specific exception?

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[JulienMaille]

I would say: ignore it and print some warning message

[JulienMaille]

can you give a look at this commit? https://github.com/pauloromeira/onegram/compare/master...neFAST:34e7f348f583c99abb74308d554c7ade4a9f6b1d#diff-97323fbaa4abdcae6b08f8df4c581b41

[Oyetomi]

How did you fix this @neFAST nefast