Open cslxiao opened 8 years ago
The comments say that the output of adaBoostApply hs is a log ratio (.5_log(p/(1-p)), so I can derive the probability as p = exp(2_hs)/(1+exp(2*hs)) But when I calculate p in this way, the output is kind of weird, so I doubt whether it is correct?
The comments say that the output of adaBoostApply hs is a log ratio (.5_log(p/(1-p)), so I can derive the probability as p = exp(2_hs)/(1+exp(2*hs)) But when I calculate p in this way, the output is kind of weird, so I doubt whether it is correct?