willpearse
commented
7 years ago - Answering your questions in order: Yes. Because you will give it a single cell from your matrix. Yes. --> I think, given that you've answered every question in your question, you do therefore understand what is going on...
- I don't really understand this question, so let's talk about it in class...
I have having a hard time keeping all of the variables straight, as there are many. On my survive function(plants.R line 69), I say that if the cell has NA, return NA, because we don't want to change anything. I then say that if there is already a plant there, they are going to compete! Lastly, if the cell is empty...and if the survival value is lower than a random draw from a uniform distribution, we still do nothing. Else, we...and that's I am stuck in the coding. I know that I need to assign the cell to the name of the plant that now occupies it. What I need to know: 1- is cell a cell in the char.matrix? How will R know that we want a single cell from our char.matrix which is (plants)? Wouldn't we have to call the whole char.matrix and then just index it? I guess I don't understand how we are calling "cell" as an argument. 2- how can I assign the plant name to the matrix? I am assuming that I need to use info$names at some point, but which of the two names do we use? I'm thinking it must be something like: cell <- info$names(?)
Separate plant.timestep question: are we going to keep time by just doing for(i in 1:100)? That is what I got from "discrete time steps." Is there a certain amount of time we need to keep?