Closed sigs closed 4 years ago
Surely the multiplicative identity belongs to the field and not the vector space (since multiplication between vectors isn't yet defined).
So: https://github.com/peeterjoot/GAelectrodynamics/blob/5d779f9b855a1787e9c98659ed5cab5603afd054/prereq_vectorspace.tex#L33 Should probably be
There exists a multiplicative identity \( 1 \in \bbR \) & \( 1 \Bx = \Bx \) \\ \hline
Or simply
\( 1 \in \bbR \) is the multiplicative identity & \( 1 \Bx = \Bx \) \\ \hline
since we assume reals are already known.
Fixed in e495adad263f1ddbd10089aeb4c121cb65580de8.
I've removed any mention of whether 1 is a member of the field or the vector space. This is consistent with what is done in the linear algebra books that I own.
Surely the multiplicative identity belongs to the field and not the vector space (since multiplication between vectors isn't yet defined).
So: https://github.com/peeterjoot/GAelectrodynamics/blob/5d779f9b855a1787e9c98659ed5cab5603afd054/prereq_vectorspace.tex#L33 Should probably be
Or simply
since we assume reals are already known.