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pekebyte / pekeUpload

jQuery html5 file uploader plugin
http://pekebyte.github.io/pekeUpload
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How to use data option ? #5

Closed double-v closed 11 years ago

double-v commented 11 years ago

Sorry just found, thanks var_dump....

kiro112 commented 11 years ago

please show how to use the data options need badly.. email me if you can jairo.malanay@gmail.com

or please give sample with data options

double-v commented 11 years ago

Hi, no prob just use Json just add the option data like this

data:'{"var:valeur"}' (important data content must be a string, that's where i was wrong)

& then in php file :

if(isset($_POST['data'])){ $json=$_POST['data']; $data=json_decode($json, true); Have a nice day.

william Le 12/08/2013 08:25, jairo a écrit :

please show how to use the data options need badly.. email me if you can jairo.malanay@gmail.com mailto:jairo.malanay@gmail.com

or please give sample with data options

— Reply to this email directly or view it on GitHub https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22475139.

kiro112 commented 11 years ago

thanks for the feedback.

kiro112 commented 11 years ago

dear sir,

i wish i'm not disturbing too much

but the sending data in peke upload still failed

i have tried this as input data: '{ site_id : "154" }' data: '{ "site_id : 154" }' data: { site_id : 154 }

but still doesnt work

On Mon, Aug 12, 2013 at 11:19 PM, double-v notifications@github.com wrote:

Hi, no prob just use Json just add the option data like this

data:'{"var:valeur"}' (important data content must be a string, that's where i was wrong)

& then in php file :

if(isset($_POST['data'])){ $json=$_POST['data']; $data=json_decode($json, true); Have a nice day.

william Le 12/08/2013 08:25, jairo a écrit :

please show how to use the data options need badly.. email me if you can jairo.malanay@gmail.com mailto:jairo.malanay@gmail.com

or please give sample with data options

— Reply to this email directly or view it on GitHub https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22475139.

— Reply to this email directly or view it on GitHubhttps://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22500846 .

kiro112 commented 11 years ago

i think this is where i make my mistake formData.append('data', options.data);

i can understand this perfectly

On Fri, Aug 23, 2013 at 9:32 AM, jairo malanay jairo.malanay@gmail.comwrote:

dear sir,

i wish i'm not disturbing too much

but the sending data in peke upload still failed

i have tried this as input data: '{ site_id : "154" }' data: '{ "site_id : 154" }' data: { site_id : 154 }

but still doesnt work

On Mon, Aug 12, 2013 at 11:19 PM, double-v notifications@github.comwrote:

Hi, no prob just use Json just add the option data like this

data:'{"var:valeur"}' (important data content must be a string, that's where i was wrong)

& then in php file :

if(isset($_POST['data'])){ $json=$_POST['data']; $data=json_decode($json, true); Have a nice day.

william Le 12/08/2013 08:25, jairo a écrit :

please show how to use the data options need badly.. email me if you can jairo.malanay@gmail.com mailto:jairo.malanay@gmail.com

or please give sample with data options

— Reply to this email directly or view it on GitHub https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22475139.

— Reply to this email directly or view it on GitHubhttps://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22500846 .

double-v commented 11 years ago

Hi,

It's your json synthax whih isn't good : http://fr.wikipedia.org/wiki/JavaScript_Object_Notation

just add your several variable in 1 string var.

data: '{ site_id : "154" }' data: '{ "site_id : 154" }' data: { site_id : 154 }

become :

data:'{site_id : "154",site_id : "154",site_id : "154"}';

Le 23/08/2013 03:38, jairo a écrit :

i think this is where i make my mistake formData.append('data', options.data);

i can understand this perfectly

On Fri, Aug 23, 2013 at 9:32 AM, jairo malanay jairo.malanay@gmail.comwrote:

dear sir,

i wish i'm not disturbing too much

but the sending data in peke upload still failed

i have tried this as input data: '{ site_id : "154" }' data: '{ "site_id : 154" }' data: { site_id : 154 }

but still doesnt work

On Mon, Aug 12, 2013 at 11:19 PM, double-v notifications@github.comwrote:

Hi, no prob just use Json just add the option data like this

data:'{"var:valeur"}' (important data content must be a string, that's where i was wrong)

& then in php file :

if(isset($_POST['data'])){ $json=$_POST['data']; $data=json_decode($json, true); Have a nice day.

william Le 12/08/2013 08:25, jairo a écrit :

please show how to use the data options need badly.. email me if you can jairo.malanay@gmail.com mailto:jairo.malanay@gmail.com

or please give sample with data options

— Reply to this email directly or view it on GitHub

https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22475139.

— Reply to this email directly or view it on GitHubhttps://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22500846 .

— Reply to this email directly or view it on GitHub https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-23138480.

kiro112 commented 11 years ago

well.. i manage to do the job, but i modify the library >.< i change the formData.append('data', option.data) to var keys = Object.keys( options.data ); var values = options.data; for(var i=0; i<Object.keys( options.data ).length; i+=1){ formData.append( keys[i], values[ keys[i] ] ); }

and i works, the data input should be {id: 121}

On Mon, Aug 26, 2013 at 8:49 PM, double-v notifications@github.com wrote:

Hi,

It's your json synthax whih isn't good : http://fr.wikipedia.org/wiki/JavaScript_Object_Notation

just add your several variable in 1 string var.

data: '{ site_id : "154" }' data: '{ "site_id : 154" }' data: { site_id : 154 }

become :

data:'{site_id : "154",site_id : "154",site_id : "154"}';

Le 23/08/2013 03:38, jairo a écrit :

i think this is where i make my mistake formData.append('data', options.data);

i can understand this perfectly

On Fri, Aug 23, 2013 at 9:32 AM, jairo malanay jairo.malanay@gmail.comwrote:

dear sir,

i wish i'm not disturbing too much

but the sending data in peke upload still failed

i have tried this as input data: '{ site_id : "154" }' data: '{ "site_id : 154" }' data: { site_id : 154 }

but still doesnt work

On Mon, Aug 12, 2013 at 11:19 PM, double-v notifications@github.comwrote:

Hi, no prob just use Json just add the option data like this

data:'{"var:valeur"}' (important data content must be a string, that's where i was wrong)

& then in php file :

if(isset($_POST['data'])){ $json=$_POST['data']; $data=json_decode($json, true); Have a nice day.

william Le 12/08/2013 08:25, jairo a écrit :

please show how to use the data options need badly.. email me if you can jairo.malanay@gmail.com mailto:jairo.malanay@gmail.com

or please give sample with data options

— Reply to this email directly or view it on GitHub

https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22475139.

— Reply to this email directly or view it on GitHub< https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-22500846> .

— Reply to this email directly or view it on GitHub https://github.com/pekebyte/pekeUpload/issues/5#issuecomment-23138480.

— Reply to this email directly or view it on GitHubhttps://github.com/pekebyte/pekeUpload/issues/5#issuecomment-23260107 .