Closed peterwoj closed 4 years ago
The call to widget.getId.toString() does not return what widget.getId().toString() does causing a device with multiple accessories to fail adding the accessories due to duplicate UUID.
widget.getId.toString()
widget.getId().toString()
The call to
widget.getId.toString()
does not return whatwidget.getId().toString()
does causing a device with multiple accessories to fail adding the accessories due to duplicate UUID.