Closed arouinfar closed 7 years ago
I've re-reviewed the user's data, and have realized that he plotted the Electric Potential versus 1/r^2, not the Electric Field. The electric potential of a point charge behaves as kq/r.
For a sanity check, I collected the voltage data using the distances in the user's table. Plotting the voltage vs. 1/r results in a linear trend.
I've already replied to the user and cc'ed phethelp, so this issue can be closed.
A teacher wrote into phethelp saying
I took a few quick measurements, and there may be something to the teacher's claim. For example, if I calculate the E-field for a +1nC charge for the scenario shown in the screenshot, I find that the equipotential voltages should be roughly 16V, 6V, and 1.5V.
I'll need to dig into this more carefully tomorrow.