Closed Avngarde closed 4 years ago
Hi there,
Please review your code. As it stands it will not work.
A couple of pointers:
return(videoInfo)
as a function is intended.console.log(videoInfo)
instead of the return to print the result to stdout.Good luck!
Everything is printed out properly, yet when i try to return the info nothing is returned, i only see a whitespace.
` function YT_get_song_info(link){