Closed ellaninomiya closed 1 year ago
If you have three parameters with only one indicating a lower bound then just specify lbound
as a vector with $-\infty$ where necessary. For example, if the 2nd parameter is bounded then lbound = c(-Inf, 0, -Inf)
.
Hi, I am using createItem() to define a item reponse function with three estimated parameters, and only one parameter needs a lower bound which can constrain it to be positive. In reference manual, createItem() has lbound argument, it seems all parameters will be affected when lbound is specified. How can I set the lower bound for just one parameter, while other parameters' bounds remains inf or being defined using different settings?