alikasundara
commented
1 year ago @zugzwang temporary workaround for you: $\sqrt{2} = \frac{1}{sin(\frac{\pi}{4})}$
Open zugzwang opened 1 year ago
alikasundara
commented
1 year ago @zugzwang temporary workaround for you: $\sqrt{2} = \frac{1}{sin(\frac{\pi}{4})}$
I have a customer that is not particularly fond of π. Is √2 on the roadmap? If so, any ETA?