Logging in requires OTP

sharunkumar commented 4 years ago

Please follow the guide below

Issues submitted without this template format will be ignored.
Please read the questions carefully and answer completely.
Do not post screenshots of error messages or code.
Put an x into all the boxes [ ] relevant to your issue (==> [x] NO spaces).
Use the Preview tab to see how your issue will actually look like.
Issues about reverse engineering is out of scope and will be closed without response.
Any mention of spam-like actions or spam-related tools/libs/etc is strictly not allowed.

Before submitting an issue, make sure you have:

[x] Updated to the lastest version v1.6.0
[x] Read the README and docs
[x] Searched the bugtracker for similar issues including closed ones
[x] Reviewed the sample code in tests and examples

Which client are you using?

[x] app (instagram_private_api/)
[ ] web (instagram_web_api/)

Describe the Bug/Error:

Please make sure the description is worded well enough to be understood with as much context and examples as possible.

I tried using this api but I am not able to log in (error log attached) plus I am getting an OTP on my mobile number registered with instagram.

Code to replicate the error must be provided below.

from instagram_private_api import Client, ClientCompatPatch

user_name = '[redacted]'
password = '[redacted]'

api = Client(user_name, password)

Paste the output of python -V here:

Code:

# Example code that will produce the error reported
from instagram_web_api import Client

web_api = Client()
user_feed_info = web_api.user_feed('1234567890', count=10)

Error/Debug Log:

> Executing task: python app\main.py <

Traceback (most recent call last):
  File "C:\Python37\lib\site-packages\instagram_private_api\client.py", line 523, in _call_api
    response = self.opener.open(req, timeout=self.timeout)
  File "C:\Python37\lib\urllib\request.py", line 531, in open
    response = meth(req, response)
  File "C:\Python37\lib\urllib\request.py", line 641, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python37\lib\urllib\request.py", line 569, in error
    return self._call_chain(*args)
  File "C:\Python37\lib\urllib\request.py", line 503, in _call_chain
    result = func(*args)
  File "C:\Python37\lib\urllib\request.py", line 649, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "app\main.py", line 6, in <module>
    api = Client(user_name, password)
  File "C:\Python37\lib\site-packages\instagram_private_api\client.py", line 208, in __init__
    self.login()
  File "C:\Python37\lib\site-packages\instagram_private_api\endpoints\accounts.py", line 50, in login
    'accounts/login/', params=login_params, return_response=True)
  File "C:\Python37\lib\site-packages\instagram_private_api\client.py", line 527, in _call_api
    ErrorHandler.process(e, error_response)
  File "C:\Python37\lib\site-packages\instagram_private_api\errors.py", line 135, in process
    raise ClientError(error_msg, http_error.code, error_response)
instagram_private_api.errors.ClientError: Bad Request
The terminal process terminated with exit code: 1

Mishul-G commented 4 years ago

Hey @sharunkumar were you able to get this working? Is this thread dead?

sharunkumar commented 4 years ago

@Mishul-G hope haven't found a way to make this work. I guess this is because I have TFA enabled on my account 🤔 maybe turning it off would make it work

Mishul-G commented 4 years ago

Yeah that’s worth a try. Are any other aspects of api working that you have tried?

sharunkumar commented 4 years ago

I just played around with the api many months ago and it seemed to be working fine. but this TFA problem is new to me

autoiue commented 4 years ago

There is a fork that provides 2FA methods here : https://github.com/pbotsman/instagram_private_api

ping / instagram_private_api