Closed Gerrit02 closed 6 years ago
hi,
sorry but i don't remember and i don't really have time to investigate it now. plz consult it with your professor / class. also providing links to specific parts of code would have increased your chances as right now i don't even know which lines r u talking about
ok tnx, I will try to discuss with the professor or class but the problem is we can not submit code.
Gerrit
Van: "Piotr Turski" notifications@github.com Aan: "piotrturski/machine-learning-coursera" machine-learning-coursera@noreply.github.com Cc: "gerrit stevens2" gerrit.stevens2@telenet.be, "Author" author@noreply.github.com Verzonden: Woensdag 13 december 2017 03:12:41 Onderwerp: Re: [piotrturski/machine-learning-coursera] learning factor Alpha (#1)
hi,
sorry but i don't remember and i don't really have to investigate it now. plz consult it with your professor / class. also providing links to specific parts of code would have increased your chances as right now i don't even know which lines r u talking about
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Hello @piotrturski , I have a question about your solution regarding to define the gradiënt for logarith regression (machine learning). (EX2 Week 3 machinge learning logistic regression)
The formular you use to define the gradiënt is: grad = (X' * (Hx - y)) / m;
But didn't you have to use the learning factor Alpha? Why is Alpha not used here? In the EX1 example there you have a for loop from 1 to itterations and alpha was defined as 0.1 I think. But for EX2 there is no for loop at all and also no alpha defined. Can you clarify a litle bit more why this is not the case here. When looking into the course Week 3 of machine learning when defining the gradiënt there is still make use of alpha and different itterations steps?