create conda recipe

[edublancas]

since jupysql-plugin is now a hard dependency for jupysql, we need to create a conda recipe for jupysql-plugin.

since jupysql-plugin is not available on conda, the PR for the new jupysql is broken: https://github.com/conda-forge/jupysql-feedstock/pull/21#issuecomment-1731748251

there is some information on how to upload packages to conda here: https://github.com/search?q=repo%3Aploomber%2Fcontributing%20conda&type=code

[neelasha23]

Please review this PR: https://github.com/conda-forge/staged-recipes/pull/24656 If it's fine I'll request a review from conda maintainers @edublancas

[edublancas]

@neelasha23 lgtm. once this is in conda, please install it from there in a new environment to ensure it works correctly

[neelasha23]

Sure! Please add a comment in the PR so that I can tick GitHub users listed in the maintainer section have posted a comment confirming they are willing to be listed there. @edublancas

[edublancas]

@neelasha23 the recipe has been merged: https://github.com/conda-forge/staged-recipes/pull/24656

please do a quick test by installing jupysql-plugin from conda and checking that things work (the connection manager, the share notebook button, sql formatting, autocompletion, etc).

if all works, we can close this

[neelasha23]

Getting error for all the features:

@edublancas

[neelasha23]

Only the ConnectorWidget seems to be working:

@edublancas

[edublancas]

I think the errors you're getting are because you're using JupyterLab 4, please try again with JupyterLab 4

[neelasha23]

Features are working fine:

Connector Widget:

New connection:

SQL Formatting:

Autocomplete:

notebook share:

However I see that it is asking for creating an account? Is it expected? I didn't get any prompt for API key:

@edublancas

[edublancas]

that's fine. it won't prompt you for an API key if you set one already. we can close this then