How to pass arguments to function in timeout

[rohitgulia]

  handleClickOnRoute = async(selectedRouteData) => {
    try {
      clearTimeout(this.timeOut);
      await this.props.setSelectRouteAction(selectedRouteData);
      await this.props.getStopsListAction(this.props.selectedRoute.id).then(()=>{
        this.timeOut = setTimeout(this.handleClickOnRoute, 5000, selectedRouteData);
      });

    } catch(err) {
      clearTimeout(this.timeOut);
      this.props.addMessageCreator(err.message, WARNING);
    }
  }

When function runs next time it passes null argument. I am not able to figure out how to pass argument to it. Normally in timeout we have third parameter to pass as argument, but that doesn't work here i guess.

[plougsgaard]

To be honest I did not know that was the official signature of setTimeout. I'll have to look into that.

In the meantime you could just wrap your function in an anonymous function to get the same result:

this.timeOut = setTimeout(() => this.handleClickOnRoute(selectedRouteData), 5000);

[plougsgaard]

I'll cut a minor release with this soon.

[rohitgulia]

I'll cut a minor release with this soon.

Thanks for the reply @plougsgaard