Closed soumitradev closed 1 year ago
On Windows, the Scanf treats \r and \n as the same, causing the first Scanf to not consume the \r, thereby causing the succeeding Scanf to register the \n instead. Adding a \n to the end of the format specifier for Scanf is sufficient to avoid this.
Closes #5
On Windows, the Scanf treats \r and \n as the same, causing the first Scanf to not consume the \r, thereby causing the succeeding Scanf to register the \n instead. Adding a \n to the end of the format specifier for Scanf is sufficient to avoid this.
Closes #5