Closed stephencelis closed 6 months ago
The set/modify of identifiedArray[n] both assume an in-place replacement of the same identity. This makes sense for _modify, but not set, which can replace a value with one that has a totally new identity.
set
modify
identifiedArray[n]
_modify
The
set
/modify
ofidentifiedArray[n]
both assume an in-place replacement of the same identity. This makes sense for_modify
, but notset
, which can replace a value with one that has a totally new identity.