Open in-die-nibelungen opened 4 years ago
The paper says that PFLD 1X and PFLD 0.25X has 12.5 Mb and 2.1 Mb, respectively. As far as I confirmed with
thop.profile
andtorchsummary.summary
, the number of parameters of PFLD 1X's seems 1.26M, about ten times smaller than 12.5Mb.What's `12.5Mb' meaning?
I confirmed it with the following code:
import numpy as np import torch from torchvision.models import MobileNetV2 from thop import profile from torchsummary import summary from models.pfld import PFLDInference # models. # MobileNetV2's are the references. pfld_backbone=PFLDInference() mobilenetv2 = MobileNetV2() mobilenetv2_025 = MobileNetV2(width_mult=0.25) # dummy input. inputs = torch.randn([1,3,112,112]) names = ['PFLD', 'MobileNetV2', 'MobileNetV2_wm-0.25'] nets = [pfld_backbone, mobilenetv2, mobilenetv2_025] # to Mega. denom = np.array((1e+6,)*2) # profiling. for name, net in zip(names, nets): rlt=profile(net, inputs=(inputs,)) print('{0}: {1[1]:.2f}M'.format(name, np.array(rlt)/denom)) #for name, net in zip(names, nets): # print(name) # summary(net, (3,112, 112))
Thanks in advance
I have the same question as you,have you figure out this? Could you please tell me why?
The paper says that PFLD 1X and PFLD 0.25X has 12.5 Mb and 2.1 Mb, respectively. As far as I confirmed with
thop.profile
andtorchsummary.summary
, the number of parameters of PFLD 1X's seems 1.26M, about ten times smaller than 12.5Mb.What's `12.5Mb' meaning?
I confirmed it with the following code:
Thanks in advance