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prajnamort / LambdaOJ2

MIT License
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判等函数 #17

Closed kainwen-zz closed 7 years ago

kainwen-zz commented 7 years ago

https://github.com/prajnamort/LambdaOJ2/blob/93d177a48c5b615c6c337d41b1a7fb5a6cca653a/main/models/problem.py#L99

个人建议一个token一个token的比较，token直接用空白split。

prajnamort commented 7 years ago

嗯， #9 已经有过了