Closed kaneplusplus closed 2 years ago
OK, looking at the code, it looks like an intersection of the different keyword argument. The match_all
argument says whether all keyword vector arguments need to appear.
Should we consider a union over trials based on *_kw argument?
If I connect and run the following two queries the former returns 26 trials and the second returns 23. Shouldn't the latter return at least as many trials as the first since the set of trials where "g12c" is a keyword in the official title is a subset of the trials where "g12c" keyword in the official title or the description?