Closed GoogleCodeExporter closed 9 years ago
Make sure your User class implement JSONAware:
class User implements JSONAware{
...
}
Original comment by fangyid...@gmail.com
on 23 Apr 2009 at 4:10
Yes I create interface JSONAware in same package and implement JSONAware. Look
at my
code : http://stargate.cnl.tuke.sk/~maly/simple
Original comment by xxxxma...@gmail.com
on 23 Apr 2009 at 6:14
I looked into your code. You should do 2 things below:
1. Use JSONAware(org.json.simple.JSONAware) from JSON.simple instead of
creating your
own;
2. class User should implement org.json.simple.JSONAware:
class User implements org.json.simple.JSONAware {
...
}
Original comment by fangyid...@gmail.com
on 23 Apr 2009 at 10:04
Ok, I pass interface org.json.simple.JSONAware into package org.json.simple.*
but
error always exist. I am dispairing. I give on server test web app which
content only
this trouble> http://stargate.cnl.tuke.sk/~maly/jquery_1/
Original comment by xxxxma...@gmail.com
on 23 Apr 2009 at 6:13
Your resultJ.java looks good. Please make sure the compiled resultJ.class is up
to
date and no old version is cached in you app classpath.
Original comment by fangyid...@gmail.com
on 27 Apr 2009 at 4:42
Original comment by fangyid...@gmail.com
on 28 Apr 2009 at 2:59
Original issue reported on code.google.com by
xxxxma...@gmail.com
on 22 Apr 2009 at 8:41