Closed GoogleCodeExporter closed 8 years ago
The top element of the stack is buffered.
Error checking is not performed until the top element is USED, so:
: add37 37 + . ;
I.E. including dot . to display the top element; would report an error.
Just adding 37 and leaving it on the stack doesn't affect anything, so in
practice this doesn't have to be reported as an error until the result is used.
So the original error steps are an arbitrary example and will not happen in an
application.
This was a design decision, waiting on the error checking until use gives about
a 30% performance increase.
By design, no change.
Original comment by prof.bra...@gmail.com
on 29 Aug 2013 at 1:17
Original issue reported on code.google.com by
prof.bra...@gmail.com
on 30 Jun 2013 at 4:14