ptwobrussell
commented
10 years ago I may be missing something, but from briefly inspecting the code again, I'm having a hard time identifying how this could happen. If the code in the "try" block fails, then it should break you out of the loop, avoiding the line of code in question that references "next_results"
Are you sure that your indentation level is correct? I can't tell from what you pasted in if you're running the code from in the notebook as-is or if you've typed it in and may have inadvertently adjusted indent levels.
I can think about this some more, but just wanted to check back first on how you are executing the code.
On Jul 9, 2014, at 3:18 AM, agarwalkushal25 notifications@github.com wrote:
On pages 25-26, there is this code:
q = '#MentionSomeoneImportantForYou'
count = 100
search_results = twitter_api.search.tweets(q=q, count=count)
twitter_api is predefined and is working fine.
statuses = search_results['statuses']
for _ in range(5): print "Length of statuses", len(statuses) try: next_results = search_results['search_metadata']['next_results'] except KeyError, e: # No more results when next_results doesn't exist break
kwargs = dict([ kv.split('=') for kv in next_results[1:].split("&") ])
The last code throws an error that 'next_results' is not defined.
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Drlenita
On pages 25-26, there is this code:
q = '#MentionSomeoneImportantForYou'
count = 100
search_results = twitter_api.search.tweets(q=q, count=count)
twitter_api is predefined and is working fine.
statuses = search_results['statuses']
for _ in range(5): print "Length of statuses", len(statuses) try: next_results = search_results['search_metadata']['next_results'] except KeyError, e: # No more results when next_results doesn't exist break
kwargs = dict([ kv.split('=') for kv in next_results[1:].split("&") ])
The last code throws an error that 'next_results' is not defined.