Closed cannawen closed 4 years ago
Unfortunately I don't have time to analyze this in detail right now, but I would bet it comes down to the number of mines. There are 5 mines remaining on the board, and maybe with the top right mine at the right, there would need to be 6.
If (y=2,x=9) is safe, then one of each set {(3,1),(3,2),(3,3),(4,1)}, {(3,4),(3,5),(3,6)}, {(2,7),(3,7)}, {(1,7),(1,8),(1,9)}, {(2,10)} and {(5,9)} is mine
So that would check out - it means there are 6 mines which is impossible.
Given the game configuration below, isn't it possible for the mine in the top right (currently marked with the red !) to be one cell to the right?